_R_P_N_T_U_T_O_R_I_A_L(1)                       rrdtool                      _R_P_N_T_U_T_O_R_I_A_L(1)

NNAAMMEE
     rpntutorial - Reading RRDtool RPN Expressions by Steve Rader

DDEESSCCRRIIPPTTIIOONN
     This  tutorial should help you get to grips with RRDtool RPN expressions as
     seen in CDEF arguments of RRDtool graph.

RReeaaddiinngg CCoommppaarriissoonn OOppeerraattoorrss
     The LT, LE, GT, GE and EQ RPN logic operators are not as tricky as they ap‐
     pear.  These operators act on the two values on the  stack  preceding  them
     (to  the  left).  Read these two values on the stack from left to right in‐
     serting the operator in the middle.  If the resulting  statement  is  true,
     then replace the three values from the stack with "1".  If the statement if
     false, replace the three values with "0".

     For  example,  think  about "2,1,GT".  This RPN expression could be read as
     "is two greater than one?"  The answer to that question is "true".  So  the
     three  values  should be replaced with "1".  Thus the RPN expression 2,1,GT
     evaluates to 1.

     Now consider "2,1,LE".  This RPN expression could be read as "is  two  less
     than or equal to one?".   The natural response is "no" and thus the RPN ex‐
     pression 2,1,LE evaluates to 0.

RReeaaddiinngg tthhee IIFF OOppeerraattoorr
     The  IF RPN logic operator can be straightforward also.  The key to reading
     IF operators is to understand that the condition part  of  the  traditional
     "if  X than Y else Z" notation has *already* been evaluated.  So the IF op‐
     erator acts on only one value on the stack: the third value to the left  of
     the  IF  value.   The second value to the left of the IF corresponds to the
     true ("Y") branch.  And the first value to the left of the  IF  corresponds
     to the false ("Z") branch.  Read the RPN expression "X,Y,Z,IF" from left to
     right like so: "if X then Y else Z".

     For  example,  consider "1,10,100,IF".  It looks bizarre to me.  But when I
     read "if 1 then 10 else 100" it's crystal clear: 1 is true so the answer is
     10.   Note  that  only  zero  is  false;  all  other   values   are   true.
     "2,20,200,IF"  ("if  2  then 20 else 200") evaluates to 20.  And "0,1,2,IF"
     ("if 0 then 1 else 2) evaluates to 2.

     Notice that none of the above examples really simulate the whole "if X then
     Y else Z" statement.  This is because computer programmers read this state‐
     ment as "if Some Condition then Y else Z".  So it's important to be able to
     read IF operators along with the LT, LE, GT, GE and EQ operators.

SSoommee EExxaammpplleess
     While compound expressions can look overly complex, they can be  considered
     elegantly simple.  To quickly comprehend RPN expressions, you must know the
     algorithm for evaluating RPN expressions: iterate searches from the left to
     the right looking for an operator.  When it's found, apply that operator by
     popping  the operator and some number of values (and by definition, not op‐
     erators) off the stack.

     For example, the stack "1,2,3,+,+" gets "2,3,+" evaluated (as "2+3") during
     the first iteration and is replaced  by  5.   This  results  in  the  stack
     "1,5,+".   Finally,  "1,5,+"  is  evaluated resulting in the answer 6.  For
     convenience, it's useful to write this set of operations as:

      1) 1,2,3,+,+    eval is 2,3,+ = 5    result is 1,5,+
      2) 1,5,+        eval is 1,5,+ = 6    result is 6
      3) 6

     Let's use that notation to conveniently solve some complex RPN  expressions
     with multiple logic operators:

      1) 20,10,GT,10,20,IF  eval is 20,10,GT = 1     result is 1,10,20,IF

     read the eval as pop "20 is greater than 10" so push 1

      2) 1,10,20,IF         eval is 1,10,20,IF = 10  result is 10

     read  pop  "if 1 then 10 else 20" so push 10.  Only 10 is left so 10 is the
     answer.

     Let's read a complex RPN expression that also has the traditional multipli‐
     cation operator:

      1) 128,8,*,7000,GT,7000,128,8,*,IF  eval 128,8,*       result is 1024
      2) 1024   ,7000,GT,7000,128,8,*,IF  eval 1024,7000,GT  result is 0
      3) 0,              7000,128,8,*,IF  eval 128,8,*       result is 1024
      4) 0,              7000,1024,   IF                     result is 1024

     Now let's go back to the first example of multiple logic operators, but re‐
     place the value 20 with the variable "input":

      1) input,10,GT,10,input,IF  eval is input,10,GT  ( lets call this A )

     Read eval as "if input > 10 then true" and replace "input,10,GT" with "A":

      2) A,10,input,IF            eval is A,10,input,IF

     read "if A then 10 else input".  Now replace A with it's  verbose  descrip‐
     tion  again and--voila!--you have an easily readable description of the ex‐
     pression:

      if input > 10 then 10 else input

     Finally, let's go back to the first most complex example  and  replace  the
     value 128 with "input":

      1) input,8,*,7000,GT,7000,input,8,*,IF  eval input,8,*     result is A

     where A is "input * 8"

      2) A,7000,GT,7000,input,8,*,IF          eval is A,7000,GT  result is B

     where B is "if ((input * 8) > 7000) then true"

      3) B,7000,input,8,*,IF                  eval is input,8,*  result is C

     where C is "input * 8"

      4) B,7000,C,IF

     At  last  we  have a readable decoding of the complex RPN expression with a
     variable:

      if ((input * 8) > 7000) then 7000 else (input * 8)

EExxeerrcciisseess
     Exercise 1:

     Compute "3,2,*,1,+ and "3,2,1,+,*" by hand.  Rewrite  them  in  traditional
     notation.  Explain why they have different answers.

     Answer 1:

         3*2+1 = 7 and 3*(2+1) = 9.  These expressions have
         different answers because the altering of the plus and
         times operators alter the order of their evaluation.

     Exercise 2:

     One may be tempted to shorten the expression

      input,8,*,56000,GT,56000,input,*,8,IF

     by removing the redundant use of "input,8,*" like so:

      input,56000,GT,56000,input,IF,8,*

     Use traditional notation to show these expressions are not the same.  Write
     an  expression  that's  equivalent to the first expression, but uses the LE
     and DIV operators.

     Answer 2:

         if (input <= 56000/8 ) { input*8 } else { 56000 }
         input,56000,8,DIV,LE,input,8,*,56000,IF

     Exercise 3:

     Briefly explain why traditional mathematic notation  requires  the  use  of
     parentheses.   Explain  why RPN notation does not require the use of paren‐
     theses.

     Answer 3:

         Traditional mathematic expressions are evaluated by
         doing multiplication and division first, then addition and
         subtraction.  Parentheses are used to force the evaluation of
         addition before multiplication (etc).  RPN does not require
         parentheses because the ordering of objects on the stack
         can force the evaluation of addition before multiplication.

     Exercise 4:

     Explain why it was desirable for the RRDtool developers  to  implement  RPN
     notation instead of traditional mathematical notation.

     Answer 4:

         The algorithm that implements traditional mathematical
         notation is more complex then algorithm used for RPN.
         So implementing RPN allowed Tobias Oetiker to write less
         code!  (The code is also less complex and therefore less
         likely to have bugs.)

AAUUTTHHOORR
     Steve Rader <rader@wiscnet.net>

1.10.0                             2026-05-23                     _R_P_N_T_U_T_O_R_I_A_L(1)
