\documentclass[a4paper,12pt]{report} \usepackage{german,ochem} \begin{document} Als Beispiel f"ur ein gleitendes Reaktionsschema soll die Synthese der Chrysanthemums"aure in Schema~\ref{chrysanth} dienen. \begin{schema} \begin{chemistry}[darv1] set("rArrowExtend",18) joinv(2,B) { joinv(2,B) { formula(T,B) { bond(30,=; -30; 30) branch { bond(150); bond(30) atom("OH",L); } bond(-30) } arrow(-90){ text(T,L){formula(C,C){atom("HBr")}}} formula(T,B) { atom("Br") bond(30; -30; 30,=) branch { bond(90); } bond(-30) }; formula(T,B,"Tosylchlorid",V,24) { ring(){ 2: bond(r); 5: bond(r) atom("SO$_2$Cl",L); } } arrow(-90) { text(T,L){formula(C,C){atom("NaOH")}} text(B,L){formula(C,C){atom("Zn")}} } formula(T,B) { ring(){ 2: bond(r); 5: bond(r) atom("SO$_2$Na",L); } }; } arrow(-90){} % 80% formula(T,B) { ring(){ 2: bond(r); 5: bond(r) atom("SO$_2$",L,R) bond(30; -30; 30,=) branch{bond(90);} bond(-30); } }; formula(T,B,"3-Methylbutens""aure",V,24) { bond(30) branch{ bond(90); } bond(-30,=; 30) atom("COOH",L) } arrow(-90){ text(T,L){formula(C,C){atom("CH$_3$OH")}}} formula(T,B) { bond(30) branch{ bond(90); } bond(-30,=; 30) atom("CO$_2$CH$_3$",L) }; } arrow(-90){ text(T,L){formula(C,C){atom("NaOCH$_3$")}}} formula(T,B) { ring() { 3: bond(r); 0: bond(r) atom("S") branch { bond(180,=C) atom("O"); bond(0,=C) atom("O"); } bond(-90) saveXY(#1) bond(-150) bond(150,=) branch { bond(-150); bond(90); } restoreXY(#1) bond(-30) branch { bond(-150); bond(-30); } bond(30) branch{ bond(90,s,S) atom("$\ominus$"); } bond(-30) atom("CO$_2$CH$_3$",L); } } bracket() arrow(-90,10){} arrow(-90,10){ text(T,L){formula(C,C){atom("KOH")}}} formula(T,B,"\textit{trans}-Chrysanthemums""aure",V,24) { ring(,,H,,3,90) { 1: bond(r,<.) atom("COOH",L); 2: bond(150,<<) bond(-150,=) branch{ bond(-90); bond(150); }; 0: bond(t); 0: bond(b); } } \end{chemistry} \caption{Chemie mit \LaTeX: Die Synthese der Chrysanthemums"aure als Beispiel f"ur die Anwendung von \texttt{ochem.sty}.\label{chrysanth}} \end{schema} \end{document}